Determine the volume in liters occupied by 14g of nitrogen gas stp

Molar mass N₂ = 28.0 g/mol

Number of moles:

n = mass / molar mass

n = 14 / 28.0

n = 0.5 moles

1 mole N₂ 22,4 ( at STP)
0.5 mole N₂ ?? Liters

L = 22.4 * 0.5 = 11,2 L

hope this helps!

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na