What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, c2h6? in this reaction, ethane is burned in the presence of oxygen (o2) to form carbon dioxide (co2) and water ((g)+(g)â(g)+(g)recall that the coefficients of the final balanced equation should be whole numbers. thus, you might need to multiply through the equation by a factor of two to obtain whole numbers in your last step. if you have trouble balancing the equation below, use the first hint to view a video of a similar equation being balanced. then, use the rest of the hints to you balance the equation, step-by-step?

Balance equation for combustion of ethane will be:

2C₂H₆(g) + 7O₂(g)> 4CO₂(g) + 6H₂O(g)

To balance the equation:

1. Balance the number of carbon atom on both side:

C₂H₆(g) + O₂(g)> CO₂(g) + H₂O(g)

1. balance the number of carbon on both side, as in reactant there are 2 but in product one,

so , multiply the CO₂, by 2 in the product.

2. Balance the number of hydrogen on both side as in reactant the number of hydrogen is 3 but in product it is 6 so, multiplythe number of  H₂O by 3,

so multiply the number of  H₂O by 3 in product.

3. Balance the number of oxygen on both side , as 1 and 2 step increases the number of oxygen and it becomes 7 , so to balance the number of oxygen on both side by mutiplying the  number of  O₂ by 7/2 in reactant .

4. Now, doubling the equation will give balance equation that is:

2C₂H₆(g) + 7O₂(g)> 4CO₂(g) + 6H₂O(g)

beta decay is the answer