Which equivalence factor should you use to convert from 106 grams of o2 to moles of o2? a.(1 mol o2/16.00 grams o2) b.(16.00 grams o2/1 mol o2) c.(1 mol o2/32.00 grams o2) d.(32.00 grams o2/1 mol o2) pls for exam

C. (1 mol O2/32.00 g O2)

To convert 106 g O2 to moles of O2, the equivalence factor is either

(1 mol O2/32.00 g O2) or (32.00 g O2/1 mol O2). We choose the one that has the desired units (mol) on top: (1 mol O2/32.00 g O2). Then,

Mass of O2= 106 g O2× (1 mol O2/32.00 g O2) = 3.31 mol O2

Notice that the unwanted units (g O2) cancel and do not appear in the answer.

“A. (1 mol O2/16.00 g O2)” is incorrect because it uses the molar mass of O (not O2).

”B. (16.00 grams O2/1 mol O2) is incorrect because it uses the wrong molar mass for O2.

“D. (32.00 g O2/1 mol O2)” is incorrect because it has the equivalence factor upside down.

3 hours because it is a decent distance.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g