A1.5m wire carries a 3 a current when a potential difference of 84 v is applied. what is the resistance of the wire?

Resistance can be calculated using equation:

Here, V denotes voltage  

I denotes current  

R denotes resistance  

Here V is given as 84 V  

I is given as 3 A  

So by putting all the values in the equation, we will get:  

R=28 ohm  

So, resistance here will be 28 ohm .

The current flowing through the wire =

The applied potential difference =

Using Ohm's Law, that is the the voltage across the two points is directly proportional to the current flowing through the two points of the conductor. The formula is:

where V is the voltage difference, I is the current and R is the resistance of the conductor.

Substituting the values in the formula:

So, the resistance of the wire is .

explanation:

i think option no d is the correct answer

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.