On analysis, an equilibrium mixture for the reaction 2h2s(g) 2h2(g) + s2(g) was found to contain 1.0 mol h2s, 4.0 mol h2, and 0.80 mol s2 in a 4.0 l vessel. calculate the equilibrium constant, kc, for this reaction.

Kc = 3.2

The chemical equation is

2H2S ⇌ 2H2 + S2

The equilibrium constant expression is

Kc ={[H2]^2[S2]}/[H2S]^2

1.Calculate the equilibrium concentrations of each component

[H2] = (4.0 mol)/(4.0 L) = 1.0 mol/L

[S2] = (0.80 mol)/(4.0 L) = 0.20 mol/L

[H2S] = (1.0 mol)/(4.0 L) = 0.25 mol/L

2.Calculate the value of the equilibrium constant

Kc = (1.0^2 x 0.20)/0.25^2 = 3.2

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.