Asample of water with a mass of 587.00 kg is heated with 87 kj of energy to a temperature of 518.4 k. the specific heat of water is 1 j-1 kg k-1. what is the initial temperature of the water?

The correct specific heat capacity of water is 4.187 kJ/(kg.K).

q = mCΔT

ΔT = q/mC = 87 kJ/[587.00 kg x 4.187 kJ/(kg.K)] = 87 kJ/(2547.8 kJ/K)

= 0.035 K

Ti = Tf - ΔT = 518.4 K - 0.0354 K = 518.365 K

the answer would be b i believe