An object with a height of 0.3 meter is placed at a distance of 0.4 meter from a concave spherical mirror. an image with a height of 0.1 meter is formed in front of the mirror. how far from the mirror is the image located?

We can use the magnification equation for this problem.

Magnification equation:

hi/h0 = di/d0

Where in hi : image size, h0 : object size, di : image distance, d0 : object distance from mirror

So plugging in the given variables we will have the corresponding equation

0.1 m / 0.3 m = di / 0.4 m

di = 0.1333333m

The generated image of the object is located 0.13 meters or 13 cm away from the mirror

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :