How many grams of kmn04 would you get if you evaporated the water from 85.75 ml of 1.27 g/l solution?

Hey there!

Volume in liters:

85.75 mL / 1000 => 0.08575 L

Therefore:

C = m / V

1.27 = m / 0.08575

m = 1.27 * 0.08575

m = 0.1089 g

hope this helps!