subject
Chemistry, 13.07.2019 21:30 ivanyeli4520

The equilibrium concentrations of the reactants and products are [ha] = 0.220 m [h3o ] = 2.00 × 10–4 m [a–] = 2.00 × 10–4 m calculate the ka value for the acid ha.

ansver
Answers: 1

Other questions on the subject: Chemistry

image
Chemistry, 21.06.2019 23:50, kylie7357
2points what is the job of a scientist? a. to answer ethical questions. b. to write laws based on his or her knowledge. c. to ask and answer scientific questions. d. to ignore facts that do not support his or her theory.
Answers: 1
image
Chemistry, 22.06.2019 02:50, Jerrikasmith28
The conventional equilibrium constant expression (kc) for the system below is: 2icl(s) ⇄ i2(s) + cl2(g) [cl2] ([i2] + [cl2])/2[icl] [i2][cl2]/[icl]2 none of the listed answers are correct [i2][cl2]/2[icl]
Answers: 2
image
Chemistry, 22.06.2019 21:50, BookandScienceNerd
Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
Answers: 1
image
Chemistry, 23.06.2019 00:00, juliannasl
How is the way a mixture is combined different from how a compound is combined?
Answers: 3
You know the right answer?
The equilibrium concentrations of the reactants and products are [ha] = 0.220 m [h3o ] = 2.00 × 10–4...

Questions in other subjects:

Konu
Mathematics, 06.04.2021 17:10