Chemistry, 13.07.2019 21:30 ivanyeli4520
The equilibrium concentrations of the reactants and products are [ha] = 0.220 m [h3o ] = 2.00 × 10–4 m [a–] = 2.00 × 10–4 m calculate the ka value for the acid ha.
Answers: 1
Chemistry, 22.06.2019 02:50, Jerrikasmith28
The conventional equilibrium constant expression (kc) for the system below is: 2icl(s) ⇄ i2(s) + cl2(g) [cl2] ([i2] + [cl2])/2[icl] [i2][cl2]/[icl]2 none of the listed answers are correct [i2][cl2]/2[icl]
Answers: 2
Chemistry, 22.06.2019 21:50, BookandScienceNerd
Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
Answers: 1
Chemistry, 23.06.2019 00:00, juliannasl
How is the way a mixture is combined different from how a compound is combined?
Answers: 3
The equilibrium concentrations of the reactants and products are [ha] = 0.220 m [h3o ] = 2.00 × 10–4...
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