If it takes 25.0 ml of m naoh solution to standardize 10.0 ml of hcl, what is the exact concentration of hcl?

-

2.5 M

Explanation: -

Volume of NaOH = 25.0 mL

= 25.0/1000 = 0.025 L

Strength of NaOH = 1 M

Number of moles of NaOH = Volume of NaoH x strength of NaOH

= 0.025 L x 1 M

= 0.025 mol

Volume of HCl = 10.0 mL = 10.0/1000 =0.01 L

The balanced chemical equation for the reaction of HCl and NaOH is

HCl + NaOH→ NaCl + H₂O

At the equivalence point,

Number of moles of HCl =Number of moles of NaOH

Strength of HCl x Volume of HCl = 0.025 mol

Strength of HCl x 0.01 L = 0.025 mol

Strength of HCl = 0.025 / 0.01 = 2.5 M

Thus If it takes 25.0 ml of M NaOH solution to standardize 10.0 ml of HCl, 2.5 M is the exact concentration of HCl

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).