The amide formed in the reaction of 3-ethylbenzoic acid and dimethylamine is

-

3-Ethyl-N,N-dimethylbenzamide.

Explanation: -

In the first step the nitrogen lone pair attacks the carbonyl carbon.

Then a OH becomes water molecule by protonation and leaves.

Final step involves proton loss to form amide.

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.