During osmosis, water moves from a region of to a region of "high solvent concentration; low solvent concentration" and "low solute concentration; high solute concentration" are correct answers. low solute concentration; high solute concentration high solvent concentration; low solvent concentration high solute concentration; low solute concentration

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Osmosis is the process by which water molecules move from a region of high solvent concentration to low solvent concentration.

Now in any solution there are just solute and solvent.

If the amount of solvent is more in a solution then the amount of solute would be less.

Again if the amount of solvent is less in a solution then amount of solute is more.

Thus we can write that :- osmosis is the movement of water molecules from a region of low solute concentration to high solute concentration.

 low solute concentration to high solute concentration

high solvent concentration to low solvent concentration

Explanation:

Osmosis is defined as the process in which molecules of a solvent tend to move through a semipermeable membrane from a region of low concentration solution to a region of more concentrated solution.

For example, absorption of water by the roots of a plant is due to osmosis.

Also, low concentration of solute means high concentration of solvent, thus water is flowing from high concentration of solvent to low concentration of solvent.

Thus, we can conclude that in case of osmosis solvent molecules move from solution having low solute concentration to high solute concentration high solvent concentration to low solvent concentration

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g