If a reaction vessel initially contains 5 mols and 10 molo2, how many moles of s will be in the reaction vessel once the reactants have reacted as much as possible? (assume 100% actual yield.)

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Zero

Explanation: -

Number of moles of sulphur S = 5 mol

Number of moles of O2 = 10 mol

The reaction between them will be synthesis type.

The product formed will be SO2.

The balanced chemical equation for this chemical reaction is

S + O2 -- > SO2

From the balanced equation we see that

1 mol of S reacts with 1 mol of O2

So, 5 mol of S will react with

= 5 mol of O2.

O2 left = 10 – 5 = 5 mol

Sulphur is limiting reagent and will be used up

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be