The ksp of agcl is 1.6 x 10-10. what is the solubility of agcl in 0.010 m fecl3? give your answer using scientific notation (1.23e-4) and to 2 significant figures (i. e., one decimal place). [blank1]

5.3 × 10⁻⁹ M

Explanation:

FeCl₃ is a strong electrolyte that ionizes according to the following equation.

FeCl₃(aq) → Fe³⁺(aq) + 3 Cl⁻(aq)

The concentration of Cl⁻ will be 3 × [FeCl₃(aq)] = 3 × 0.010 M = 0.030 M

We can find the solubility (S) of AgCl using an ICE Chart.

        AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

I                           0            0.030

C                         +S            +S

E                          S           0.030 + S

The solubility product (Ksp) is:

Ksp = 1.6 × 10⁻¹⁰ = [Ag⁺].[Cl⁻] = S . (0.030 + S)

In the term (0.030 + S), S <<< 0.030, so we can neglect S to simplify calculations.

1.6 × 10⁻¹⁰ = 0.030 S

S = 5.3 × 10⁻⁹ M

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

c. orbital shape i hope this is correct