Chemistry, 14.07.2019 09:00 ethangeibel93

Calculate the theoretical yield of benzil assuming you begin with 2.72 grams of benzoin.

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Answer from: TamB01

Answer : The correct answer for theoretical yield = 2.73 g

Theoretical yield : It is defined as maximum amount of yield that is expected to be produce from reactants . The theoretical yield is decided by amount of product formed by Limiting Reagent .

Theoretical yield can be calculated bu using stroichiometric relation between mole of limiting reactant and product .

The reaction of Benzil can be written as :

one mole of Benzoin produces one mole of Benzil ( Image ) .

Since only one reactant , Benzoin is present so limiting reactant can be considered as Benzoin .

Theoretical yield can be calculates in following steps :

Step 1 : Conversion of mass of Benzoin to its mole .

Mass can be converted to mole using following formula :

$Mole = \frac{Mass (g)}{Molar mass \frac{g}{1 mol}}$

Molar mass of Benzoin (C₁₄H₁₂O₂ ) = 212.24 $\frac{g}{mol}$

Plugging value of Mass and molar in mole formula :

$Mole = \frac{2.72 g}{212.24 \frac{g}{mol}}$

Mole = 0.013 mol

Step 2 : To find mole ratio of Benzil to Benzoin .

Mole ratio can be find out from balanced reaction . From balanced reaction one mole of Benzoin giving one mole of Benzil , Hence mole ratio = 1 : 1

Step 3 : Find mole of Benzil

$Mole of Benzil = 0.013 mol of Benzoin * \frac{1 mole of Benzil }{1 mole of Benzoin}$

Mole of Benzil = 0.013 mol

Step 4 : To find mass of Benzil

Molar mass of Benzil (C₁₄H₁₀O₂ ) = 210.232 $\frac{g}{mol}$

Plugging value in mole formula

$0.013 mole of Benzil = \frac{mass of Benzil }{210.232 \frac{g}{mol}}$

Multiplying both side by 210.232 $\frac{g}{mol}$

$0.013 mol * 210.232 \frac{g}{mol} = \frac{mass of benzil}{210.232 \frac{g}{mol}} * 210.232 \frac{g}{mol}$

Mass of Benzil = 2.73 g

Hence Theoretical mass of Benzil = 2.73 g

Calculate the theoretical yield of benzil assuming you begin with 2.72 grams of benzoin.

Answer from: Quest

c8h10 is your answerr

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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Calculate the theoretical yield of benzil assuming you begin with 2.72 grams of benzoin....