In the reaction mgcl2 + 2koh mg(oh)2+ 2kci, if 3 moles mgch are added to 4 moles koh, what determines how much mg(oh)2 is made?

-

KOH determines how much Mg(OH)2 is made.

2 mol of Mg(OH)2 formed

Explanation:-

The balanced equation is

MgCl2 + 2KOH --> Mg(OH)2+ 2KCI,

From seeing the coefficients we notice

2 mol of KOH reacts with 1 mol of MgCl2

4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2

3 moles of MgCl2 was added but only 2 mol react.

So we see there is excess MgCl2 .

Hence KOH is the limiting reactant.

So KOH determines how much Mg(OH)2 is made.

We see from the balanced chemical equation,

2 mol of KOH gives 1 mol of Mg(OH)2.

4 mol of KOH will give 1 x 4 /2 = 2 mol of Mg(OH)2.

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".