Ahydraulic system is designed to lift cars for inspection in a service station. the narrow end of the system has a surface area of 5.00 cm2, and the lift platform (the wide end) has a surface area of 725 cm2. if a force of 81.0 newtons is applied to the narrow end, how much upward lift force will be exerted at the wide end? use the following formula: 0.559 n 11,745 n 44.75 n 293,625 n

Answer : The correct answer for force = 11.745 N .

Hydraulic system is a system which is operated by moving liquid in a definite area which is under pressure . It uses the force which is produced due to difference in pressure at two ends of a system .

It basically uses oil or water ( incompressible liquids ) , which can relocate the force from one area to other in the fluid .

The force around different areas can be calculated using Pascal's Principle.

Pascal's Principle : It states that if there in increase in pressure in any area in fluid , there will be equal to increase in pressure at other area . It can be expressed as :

---------Equation (1)

, where P1 = pressure in one area P2 = pressure in other area .

Pressure is defined as force acting per unit area . Hence , Pressure and force can be related as :

Where unit of pressure= pascals(p) Force= newton(N)

Area = meter square (m²)

On plugging value of pressure in equation (1) :

------ Equation (2)

Where , F1 = force at one area A1 = area of one area

F2 = force at other area A2 = area of other area

Given : F 1 = 81 N A1 = 5 cm² or 0.0005 m² ( 1 m²= 10000 cm²)

F2 = ? A2 = 725 cm² or 0.0725 m²

Plugging these value in equation (2) :

Multiplying both side by 0.0725 m²

F2 = 11,745 N

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

a