What is the poh of a 0.0010 m solution of calcium hydroxide (ca(oh)2)

The pOH is: " 2.40 " .

The pOH value of a 0.0010 M solution of calcium hydroxide;

Ca(OH)₂ ; is:

" 2.40 " .

Explanation:

Calculate the pOH of a 0.0010 M solution of Ca(OH)₂ .

Note that:

"M" represents the concentration in "Molarity" ;

(that is; "moles of solute per Liter of solution" ; or, "mol / L " } ;

and that for our purposes, anything notes in "brackets" refers to "concentration"; in "M" {"Molarity" ; as explained above.}.

Note that "calcium hydroxide", that is; " Ca(OH)₂ " ;

→ dissociates into the following ions, as follows:

→ Ca(OH)₂ → Ca²⁺ + 2 OH⁻ ;

Therefore, the [OH⁻] equals: {2 * 0.0010} M = 0.0040 M .

For every Ca(OH)₂ you produce 2 OH⁻ .

Note: pOH = - log [OH⁻] ;

pOH = - log ( 0.0040) = 2.3979400086720375 ;

→ round to: " 2.40 " .

The pOH is: " 2.40 " .

The pOH value of a 0.0010 M solution of calcium hydroxide; Ca(OH)₂ ; is:

" 2.40 " .

sure what is it? ^w^