How many moles of ag can be produced if 350. g of cu are reacted with excess agno3 according to the equation cu(s) + 2agno3(aq) ® 2ag(s) + cu(no3)2(aq)?

The moles of Ag produced will be 11.02 moles.

Explanation:

To calculate the number of moles, we use the equation:

For copper:

Given mass of copper = 350 g

Molar mass of copper = 63.5 g/mol

Putting values in above equation, we get:

For the given chemical equation:

Silver nitrate is present in excess, so it is considered as an excess reagent and copper is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of copper produces 2 moles of silver.

So, 5.51 moles of copper will produce = of silver.

Thus, the moles of Ag produced will be 11.02 moles.