What is the maximum mass of s8 that can be produced by combining 89.0 g of each reactant?

Answer : We can produce 125.7 g of .

Explanation : The reaction will be

The molecular mass of is 64.1 g/mol

and molecular mass of is 34.1 g/mol

For every mole of we would need twice of moles, so for every 3 moles of we need 16 moles of

Now, we can calculate number of moles

2.61 X (3/16) = 0.49 moles

Here, the molecular mass of is 256.8 g

multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of .

Hence, 125.7 g of will be produced.

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