Consider the reaction h2so4 + 2 naoh -> na2so4 + 2h2o as it represents an acid-base tritration. the equivalence point occurs when 23.23 ml of 0.2685 m naoh is added to a 40.12 ml portion of h2so4. what is the molar concentration of h2so4?

The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
            moles NaOH = c · V = 0.2685 mmol/mL · 23.23 mL = 6.237255 mmol
            moles H2SO4 = 6.237255 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.1186275 mmol
Hence
            [H2SO4]= n/V = 3.1186275 mmol / 40.12 mL = 0.07773 M
The answer to this question is  [H2SO4] = 0.07773 M

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