What mass, in grams, of oxygen gas (o2) is contained in a 10.5-liter tank at 27.3 degrees celsius and 1.83 atmospheres? show all of the work used to solve this problem.

To find the mass of O₂ in the container we can use the ideal gas law equation 
PV = nRT
where P - pressure - 1.83 atm
V - volume - 10.5 L
n - number of moles of O₂
R - universal gas constant - 0.0821 L.atm/mol.K
T - temperature in kelvin - 27.3 °C + 273 = 300.3 K
substituting the values in the equation 
1.83 atm x 10.5 L = n x 0.0821 L.atm/mol.K x 300.3 K
n = 0.779 mol 
the number of moles of O₂ are 0.779 mol 
mass of O₂ = number of moles x molar mass
mass of O₂ = 0.779 mol x 32 g/mol = 24.9 g
therefore mass of O₂ in the container is 24.9 g

Cis the