In the reaction mg (s) + 2hcl (aq) h2 (g) + mgcl2 (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of a 1.0 m hcl in an excess of mg? 0.75 moles 1.0 moles 0.038 moles 0.075 moles

The answer is .038 because it rounded from .0375 to .038

☆ionisation energy increases across a period from na -> ar☆ionisation energy decreases down a group from li -> fr☆ionic radius decreases across a period from na -> cl☆ionic radius increases down a groupfrom f -> ii hope it clarifies your doubts

The correct answer is "hydrogen".