What is the complete ionic equation for the reaction 2koh(aq) + h2so4(aq) 2h2o(l) + k2so4(aq)?

To find the complete ionic equation:

Consider:

Equation for the dissociation of the strong base in aqueous solution:

KOH  (aq)> K⁺(aq) + OH⁻(aq)

Equation for the dissociation of the strong acid in aqueous solution:

H₂SO₄(aq)>2H⁺(aq) + SO₄²⁻(aq)

On the product' side, potassium sulfate that is a ionic compound:

K₂SO₄(aq)>2K⁺  +SO₄²⁻  

Water, a covalent compound:

So net balanced equation will be:

K⁺(aq) + OH⁻(aq) +2H⁺(aq) + SO₄²⁻(aq)>2K⁺  + SO₄²⁻  +H₂O(l)

Net ionic equation by eliminating the spectator ions:

OH⁻(aq) +2H⁺(aq)>H₂O(l)

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.