For the reaction co+2h2=ch3oh at 700 k, equilibrium concentrations are [h2]=0.072 m, [co]= 0.020m, and [ch3oh]= 0.030 m. calculate k

The balanced equation for the reaction is

CO(g) + 2H₂(g) ⇄ CH₃OH(g)

The given concentrations are at equilibrium state. Hence we can use them directly in calculation with the expression for the equilibrium constant, k. expression for k can be written as

   k = [CH₃OH(g)] / [CO(g)] [H₂(g) ]²

[H₂]=0.072 M
[CO]= 0.020M
[CH₃OH]= 0.030 M

From substitution,

   k = 0.030 M / 0.020 M x (0.072 M)²

   k = 289.35 M⁻²

Hence, equilibrium constant for the given reaction at 700 K is 289.35 M⁻².

the answer to your question is c.

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