Atmospheric pressure decreases as altitude increases. in other words, there is more air pushing down on you at sea level, and there is less air pressure pushing down on you when you are on a mountain. if hexane (c6h14), octane (c8h18), and octanol (c8h17oh) are heated evenly at different altitudes, rank them according to the order in which you would expect them to begin boiling. rank from first to last. to rank items as equivalent, overlap them. view available hint(s) octane at high altitudeoctane at sea levelhexane at high altitudeoctanol at sea level

Boiling point is the temperature at which vapour pressure equals atmospheric pressure.

As, we move at higher altitudes, atmospheric pressure decreases. Hence, temperature to reach the boiling point will decrease.

Further, boiling point is higher for longer chain compounds. Hence, octane (C8H18) and octanol (C8H17OH) will have higher boiling point as compared to hexane (C6H14). Further, intermolecular forces of interaction are more stronger in octanol, due to presence of OH group, as compared to octane.

Hence, boiling points will be in following order: 
                                              Octanol > Octane > Hexane

Thus, hexane will boil first, followed by octane and lastly octanol.

While unproven, it uses facts to support part of a conclusion. it is still factual and has predictive power, however.

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is  2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry  problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that     10 dm = 1 m  ⇔ 10³ dm³ = 1 m³then we use the fact that     10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting:     now we have to find the moles of hydrochloric  acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by    molar mass = (mass ca) + (mass c) + 3(mass o)    = 40 + 12 + 3(16)    = 100 g/molconvert the given 5 g to moles:     mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis    mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃)    = 0.05 mol hcl * 2    = 0.1 mol hcl  we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get     volume = moles / concentration    volume = 0.1 mol / (0.002 mol/cm³)    volume = 50 cm³