Chemistry, 19.07.2019 10:00 pinkycupcakes3oxbqhx

How many grams of na2s do we need to dissolve in 200ml of water to get a solution that is 0.2 m?

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We know that the molarity of a solution is calculated by the following equation:

$Molarity = \frac{# moles}{L}$

That being said we are given two of the 3 things that we need: Volume of water, as well as the molarity of the solution. Let's plug those in to the equation to find how many moles of $Na_{2}S$ that we need:

$0.2 M = \frac{moles}{0.2 L}$ => moles =0.04

This means that we have 0.04 moles of $Na_{2}S$ .

In order to calculate the number of grams that we need for this solution, we must first calculate how many grams of $Na_{2}S$ are in 1 mole. We do this by taking the atomic masses of each element from the periodic table and adding them together.

Na = 22.99 g
S = 32.06 g

We have 2 Na's, and we have 1 S. So lets add them together:

2(22.99) + (32.06) = $\frac{78.04g}{mol}$ .

Since we need 0.04 moles of $Na_{2}S$ , we can multiply the molar weight of the molecule times the amount of moles needed to find the total grams that we need for the solution:

$\frac{78.04g}{mol}*0.04 moles = 3.1216 g$

Now we know that in order to make a 0.2 M solution of $Na_{2}S$ , we must use 3.1216 grams.

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Answer from: Quest

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