When this equation is balanced, the coefficient in front of h3po4 is -?

When the unbalanced reaction equation is:

Ca(NO3)2 + H3PO4 → Ca3(PO4)2 + HNO3

this is not balanced equation as the numbers of all the atoms are not equal on both sides of the equation.

we have 1 C atom of the left side and 3 atoms on the right side.

we have 2 of NO3 group on the left side and  1 of NO3 group on the right side

and we have 3 H atoms on the left side and 1 atom on the right side.

and there is 1 of PO4 group on the left side and 2 of PO4 group on the right side.

so we have to balance the equation first:

we put 3 Ca(NO3)2 instead of Ca(NO3)2 to make C atoms equal on both sides.

and we put 6HNO3 instead of HNO3 to make NO3 group equals on both sides.

and we put 2 H3PO4 instead of H3PO4

so the final balanced equation will be:

3Ca(NO3)2 + 2H3PO4 → Ca3(PO4)2  + 6HNO3

∴ the coefficients in front of H3PO4 will be 2