Asample of brass has a specific heat of 380 j/kg°c. if 1410 joules of heat is applied to a 1.5 kg piece and the initial temperature is 2.50°c, what will be the final temperature? q= (m) (csp) (δt) δt= tfinal - tinitial a .98°c b .003°c c 5.5°c d 3°c

Heat energy supplied raises the temperature of a mass of material. the formula is as follows
Q = m x Csp x ΔT
Q - heat energy supplied
m - mass of brass
Csp - specific heat 
ΔT - change in temperature 

substituting the values in the equation
1410 J = 1.5 kg x 380 J/kg°C x ΔT
ΔT = 2.47 °C
since ΔT =  T final - T initial 
and T initial = 2.50 °C
2.47 = x - 2.50 
x = 4.97 °C

answer should be 4.97 °C

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