How does fluorine react with ethene? 1. by substituting hydrogen with fluorine. 2. by breaking a carbon double bond and adding fluorine. 3 by removing hydrogen because of fluorine’s attraction to hydrogen’s nucleus. 4. fluorine and ethene do not react spontaneously.

Option 3: By removing hydrogen because of fluorine's attraction to hydrogen's nucleus.

The reaction of ethene and halogen generally breaks the carbon-carbon double bond and substitution of halogen on carbon takes place, this is known as halogenation reaction. This is in the case of reaction of ethene with chlorine, bromine and iodine. In the case of fluorine,  due to high electronegativity it get attracts to the nucleus of hydrogen and form hydrogen fluorine gas. Therefore, halogentaion reaction do not take place in the case of ethene and iodine.

Ethene explosively reacts with fluorine to form carbon and hydrogen fluoride gas. The reaction is as follows:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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