If you add 500 kj of heat to 500 g of water at 50.0°c, how much water is left in the container? the latent heat of vaporization of water is 2.26 ×103 j/g and its specific heat is is 4.190 j/(g∙k)

First, we will get the heat required to raise the 500 g of water from 50°C to 100°C = m*C*ΔT 

when m is the mass = 500 g 

and C is the specific heat capacity of water = 4.19

ΔT change in temperature = 50 °C

by substitution:

q = 0.5 Kg * 4.19 * 50°C

   =104.75 KJ

∴ heat left to boil the water= 500KJ - 104.75KJ = 395 KJ

the heat required to boil water from 100°C to steam = mass *latent heat of vaporization

  395KJ     = M * 2.26 x 10^3

 Mass = 0.17Kg = 170 g

∴ water remain= 500 g - 170 = 330 g

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