How many moles of pb(no3)2 are required if 8 moles of pbci2 are produced?

PbCl₂ can be synthesized from Pb(NO₃)₂ using various reagents. I will be using HCl as follow,

                     Pb(NO₃)₂  +  2 HCl    →     PbCl₂  +  2 HNO₃

According to equation,

                       1 mole of PbCl₂ is formed by  =  1 mole of Pb(NO₃)₂
So,
          8 moles of PbCl₂ will be produced by  =  X moles of Pb(NO₃)₂

Solving for X,
                       X  =  (8 mol × 1 mol) ÷ 1 mol

                       X  =  8 mol of Pb(NO₃)₂
Result:
            8 mol of Pb(NO₃)₂ are required to produce 8 moles of PbCl₂.