Business, 13.09.2021 03:30 anthonyalvar6636

Suppose that the weight of an newborn fawn is Uniformly distributed between 1.8 and 3.3 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. The mean of this distribution is
The standard deviation is
The probability that fawn will weigh exactly 2.1 kg is P(x = 2.1) =
The probability that a newborn fawn will be weigh between 2.1 and 2.7 is P(2.1 < x < 2.7) =
The probability that a newborn fawn will be weigh more than 2.1 is P(x > 2.1) =
P(x > 2.5 | x < 3.1) =
Find the 66th percentile.

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Suppose that the weight of an newborn fawn is Uniformly distributed between 1.8 and 3.3 kg. Suppose...