भबड़े भाई ने शुरू मे पढाई का कैमा डर दिखलाया - Class 10 Bade Bhai Saahab

Best answer would be marked brainliest​

Edit: I hv accidentally chooses the subject as Business instead of Hindi

Add the mips assembly language instructions (after main: ) to complete the following (in this order). do not skip steps. use other registers as needed. actions: 1. initialize the register $s0 to 35 2. prompt the user to enter a number, read the number and then put it into register $s1 3. prompt the user to enter a number, read the number and then put it into register $s2 4. store the value in $s1 into the memory at address 0x10010000. 5. store the value in $s2 into the memory at address 0x10010004. 6. calculate the value of $s0 - $s1 $s2 and store the result in the memory at address 0x10010008. 7. print the following output each on its own line. you will need to determine the location of each of the strings from the beginning of the memory segment a. your name b. the value in address 0x10010000 c. the value in address 0x10010004 d. the value in address 0x10010008 8. exchange or swap the values in $s1 and $s2 9. set the value in $s0 to -$s0

Match the different financial task to their corresponding financial life cycle phases

A$100 million interest rate swap has a remaining life of 10 months. under the terms of the swap, the six-month libor is exchanged semi-annually for 12% per annum. the six-month libor rate in swaps of all maturities is currently 10% per annum with continuous compounding. the six-month libor rate was 9.6% per annum two months ago. what is the current value of the swap to the party paying floating? what is its value to the party paying fixed?