A bottling operation has a mean fill level of 10.01 ounces with a standard deviation of 0.25 ounces. Random samples of 20 bottles are periodically taken to monitor the process average and the process mean is tracked using a control chart. Determine the upper and lower control limits for the chart that will include roughly 92% of the sample means when the process is in control.

The upper limit is 10.1

The lower limit is 9.91

Explanation:

Given that:

The mean fill level (μ) = 10.01 ounces,

Standard deviation (σ) = 0.25 ounces

Number of sample bottles (n) = 20

The limits of the sample mean = 92% = 0.92

α = 1 - 0.92 = 0.08

The z value of 0.04 is the same as the z value of 0.46 (0.5 - 0.04). From the probability distribution table:

The margin of error (e) is given by:

The upper limit = μ + e = 10.01 + 0.1= 10.1

The lower limit = 10.01 - 0.1 = 9.91

metallurgy is your answer

the "study of metals and the process of refining ("

note that it says metal. metallurgy has the word "metal" in it, and so is most likely your answer (and is your answer).

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