The following information is provided for each division. Investment Center Net Income Average Assets Cameras and camcorders $ 5,850,000 $ 27,800,000 Phones and communications 2,076,000 17,300,000 Computers and accessories 800,000 15,000,000 Assume a target income of 12% of average invested assets. Required: Compute residual income for each division. (Enter losses with a minus sign.)

Add the mips assembly language instructions (after main: ) to complete the following (in this order). do not skip steps. use other registers as needed. actions: 1. initialize the register $s0 to 35 2. prompt the user to enter a number, read the number and then put it into register $s1 3. prompt the user to enter a number, read the number and then put it into register $s2 4. store the value in $s1 into the memory at address 0x10010000. 5. store the value in $s2 into the memory at address 0x10010004. 6. calculate the value of $s0 - $s1 $s2 and store the result in the memory at address 0x10010008. 7. print the following output each on its own line. you will need to determine the location of each of the strings from the beginning of the memory segment a. your name b. the value in address 0x10010000 c. the value in address 0x10010004 d. the value in address 0x10010008 8. exchange or swap the values in $s1 and $s2 9. set the value in $s0 to -$s0

Which statement best explains the relationship between points a and b? a. consumption reaches its highest point, and then supply begins to fall. b. inflation reaches its highest point, and then the economy begins to expand. c. production reaches its highest point, and then the economy begins to contract. d. unemployment reaches its highest point, and then inflation begins to decrease.

Yowell company granted a sales discount of $360 to a customer when it collected the amount due on account. yowell uses the perpetual inventory system. which of the following answers reflects the effects on the financial statements of only the discount? assets = liab. + equity rev. − exp. = net inc. cash flow a. (360 ) = na + (360 ) (360 ) − na = (360 ) (360 ) oa b. na = (360 ) + 360 360 − na = 360 na c. (360 ) = na + (360 ) (360 ) − na = (360 ) na d. na = (360 ) + 360 360 − na = 360 na