A company is to hire two new employees. They have prepared a final list of thirteen candidates, all of whom are equally qualified. Of these thirteen candidates, eight are women. If the company decides to select two persons randomly from these thirteen candidates, what is the probability that both of them are men? Round your answer to four decimal places.

0.1282

Explanation:

Total number of possible outcome( total candidates) = 13

Total number of men = 13 - 8 = 5

Total number of women = 8

Number of candidates to be selected = 2

Find the probability that both are men :

Probability of 1st candidate being a male = required outcome ÷ total possible outcome = 5/13

Probability of second candidate being a male, means we now have 4 men left and a total of 12 = 4/12

Therefore, P = (5/13) × (4/12)

P = (5/13) ×(1/3) = 5/39 = 0.1282

explanation:

a gas is not used in hydraulic machines as the fluid because gas is easily compressible and so if a gas is used, the energy would mostly go into compressing a gas. therefore a liquid is used in hydraulic machines as the fluid.