A car rental agency rents 210 cars per day at a rate of 30 dollars per day. For each 1 dollar increase in the daily rate, 5 fewer cars are rented. At what rate should the cars be rented to produce the maximum income, and what is the maximum income

$36

$6466

Explanation:

For each 1 dollar increase, 5 fewer cars are rented. If y is added to the daily rate. They will rent 210 - 5y at 30 + y dollars.

Hence 210 - 5y × 30 + y = income.

F(y) = 210 - 5y × 30 + y

F(y) = 6300 + 210y - 150y -5y^2

F(y) = -5y^2 + 60y + 6300

To maximize income, we get the first derivative

F(y) = -5y^2 + 60y + 6300

F'(y) = -10y + 60

-10y + 60 = 0

10y = 60

y = 6

Therefore, the should increase their rate by $6, hence they should charge $36.

To find max income, put 7 into y

F(y) = -5×7^2 + 60×7 + 6300

= -254 + 420 + 6300

= $6466

Max income = $6466

idk sorry

explanation:

hi,

henry is an economist and wants to understand the relationship between inflation and consumer spending habits. for his research, he needs the consumer price index for 2014 and the inflation rate. based on the prices of goods given, what will he find to be the cpi and inflation rate for 2014? assume that a consumer’s basket for three consecutive years consists of the following:

you dont privide answer choices.

answer - 15% of a inflatation rate is 15% less in cpi