As noted in your text, global segmenting, targeting, and positioning are more complicated than domestic segmenting and positioning because of cultural nuances, significant subcultures within countries, and:.
A. currency differences.
B. antidiscrimination regulations prohibiting segmentation and targeting in developing countries.
C. differences in the way consumers see themselves and in the way they see products and services.
D. complications due to franchising issues.
E. the taxes imposed by some foreign countries on marketing activities.

Add the mips assembly language instructions (after main: ) to complete the following (in this order). do not skip steps. use other registers as needed. actions: 1. initialize the register $s0 to 35 2. prompt the user to enter a number, read the number and then put it into register $s1 3. prompt the user to enter a number, read the number and then put it into register $s2 4. store the value in $s1 into the memory at address 0x10010000. 5. store the value in $s2 into the memory at address 0x10010004. 6. calculate the value of $s0 - $s1 $s2 and store the result in the memory at address 0x10010008. 7. print the following output each on its own line. you will need to determine the location of each of the strings from the beginning of the memory segment a. your name b. the value in address 0x10010000 c. the value in address 0x10010004 d. the value in address 0x10010008 8. exchange or swap the values in $s1 and $s2 9. set the value in $s0 to -$s0

One question from a survey was "how many credit cards do you currently have? " the results of the survey are provided. complete parts (a) through (g) below. click the icon to view the survey results. (a) determine the mean number of credit cards based on the raw data. the mean is 3.113.11 credit cards. (type an integer or a decimal. do not round.) (b) determine the standard deviation number of credit cards based on the raw data. the standard deviation is 1.9111.911 credit cards. (round to three decimal places as needed.) (c) determine a probability distribution for the random variable, x, the number of credit cards issued to an individual. x (# of cards) p(x) x (# of cards) p(x) 1 0.280.28 6 nothing 2 nothing 7 nothing 3 nothing 8 nothing 4 nothing 9 nothing 5 nothing 10 nothing (type integers or decimals. do not round.)

What are two benefits of consumer programs