Amethods and measurements analyst for timepiece, inc., needs to develop a time standard for the task of attaching a watch to a wristband. in a preliminary study, he observed one of his workers perform this task five times, with the following results:

observation 1 2 3 4 5
time (seconds) 27 19 20 21 13
1. what is the observed time for this task?

2. what is the normal time for this task if the employee worked at a 20 percent faster pace than average?

3. what is the standard time for this task if the employee worked at a 20 percent faster pace than average and an allowance of 20 percent of job time is used?

Check the following calculations

Explanation:

1. Observed Time for the task,

OT = Sum of Task Times / Total Number of Observations = (27 + 19 + 20 + 21 + 13) / 5 = 20 seconds.

2. Performance Rating, PR = 120% = 1.20

Normal time for the task, NT = Observed Time for the task (OT)  Performance Rating (PR) = 20 x 1.20 = 24 seconds.

3.  Performance Rating, PR = 120% = 1.20

Allowance for the task, Allowance = 20% = 0.20 (based on job time).

Standard time for the task

ST = Normal Time for the task (NT) * (1 + Allowance) = 24 x (1 + 0.20) = 28.8 seconds.

you will have $2593.74 in 10 years if you set aside $1,000 at 10%

you will have $9321.91 in 20 years if you set aside $2000 at 8%

you will have $1469.32 in 5 years if you set aside $1000 at 8%

you will have $1296.87 in 10 years if you set aside $500 at 10%

you will have $239.66 in 15 years if you set aside $100 at 6%

you will have $4660.96 in 20 years if you set aside $1000 at 8%

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