Business, 09.10.2019 04:00 adrianamunn

Select vendor_name, count(*) as number_of_invoices, max(invoice_total - payment_total - credit_total) as balance_due from vendors v join invoices i on v. vendor_id = i. vendor_id where invoice_total - payment_total - credit_total > (select avg(invoice_total - payment_total - credit_total) from invoices) group by vendor_name order by balance_due desc

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Select vendor_name, count(*) as number_of_invoices, max(invoice_total - payment_total - credit_total...