# The chromosome manufacturing company produces two products, x and y. the company president, jean mutation, is concerned about the fierce competition in the market for product x. she notes that competitors are selling x for a price well below chromosome's price of $13.50. at the same time, she notes that competitors are pricing product y almost twice as high as chromosome's price of $12.50.ms. mutation has obtained the following data for a recent time period: product x product y number of units 11,000 3,000 direct materials cost per unit $3.23 $3.09 direct labor cost per unit $2.22 $2.10 direct labor hours 10,000 3,500 machine hours 2,100 1,800 inspection hours 80 100 purchase orders 10 30ms. mutation has learned that overhead costs are assigned to products on the basis of direct labor hours. the overhead costs for this time period consisted of the following items: overhead cost item amount inspection costs $16,200 purchasing costs 8,000 machine costs 49,000 total $73,200using direct labor hours to allocate overhead costs determine the gross margin per unit for product x. choose the best answer from the list below. a. $1.93b. $3.12c. $7.38d. $2.43e. $1.73using activity-based costing for overhead allocation, determine the gross margin per unit for product y. choose best answer from list below. a. $10.07b. ($2.27)c. ($5.23)d. ($7.02)e. $7.02

The equation shows that the mass of the products is always equal to that of the reactants.

Explanation; Einstein's equation E=mc²; where the E stands for energy and the m stands for mass, a measurement of the quantity of matter. From the equation energy and matter are interchangeable. Energy is equivalent to matter multiplied by the speed of light squared. The grand total remains constant, but energy regularly changes form into matter and matter into energy. Einstein's equation gave rise to various advances in technology technological, from nuclear power and nuclear medicine to the inner workings of the sun. The equation tells us that matter and energy are one. 3. Answer;The amount of energy released in nuclear reactions is so much larger than the energy released in chemical reactions

Explanation; Nuclear reactions such as nuclear fission and fusion release much larger energy as compared to chemical reactions because tremendous amounts of energy is released at one time. In nuclear reactions, for example nuclear fission, when an atom is split inside a nuclear power plant or an atomic bomb, the resulting energy releases at the speed of light. E = mc2 is the key to understanding why and how energy is released in nuclear reactions. The equation relates to the reductions in mass and the numerous production of energy that occur in nuclear reactions. 4. Answer:

The above statement is TRUE

Explanation; The Law of conservation of mass states that during any physical or chemical change, the total mass of the products is equal to the total mass of reactants provided. Nuclear reactions violate the law of conservation of mass. For instance the nuclear fusion reactions occurring in the sun as a result of fusion between hydrogen nuclei causing formation of helium nuclei. The conservation of mass is not observed as some mass is converted to energy. 5. Answer;The statement "In both nuclear fission and nuclear fusion reactions, energy is converted to mass" is FALSE

Explanation; Instead, mass is converted to energy during both nuclear fission and nuclear fusion.Nuclear fission and nuclear fusion are the two types of nuclear reactions. Nuclear fusion involves the combining of two small nuclei to form a larger nuclei coupled with the release of energy. Nuclear fission on the other hand involves the splitting of a heavy larger nuclei to yield smaller nuclei and is also coupled with the release of energy. In nuclear fission, the resultant products have a slightly smaller nuclear mass as compared to heavy nucleus. This difference in mass is because some mass is converted to energy during the fission. Similarly in nuclear fusion some of the mass of the initial nuclei is converted into energy in the form of heat or light.

6. Answer;

The above statement is FALSE

Explanation; In nuclear reactions some mass is converted into energy. The mass "lost" is NOT used to convert energy into mass.In nuclear fission, the resultant products have a slightly smaller nuclear mass as compared to heavy nucleus. This difference in mass is because some mass is converted to energy during the fission. Similarly in nuclear fusion some of the mass of the initial nuclei is converted into energy in the form of heat or light. 7. Answer;

=2.736 * 10^15 J

Solution;

E = mc² ; where E is the energy in joules, m is the mass in kg, and c is the speed of light (m/s).

Mass = 0.0304 kg

E = (0.0304)(3×10^8)²

Energy = 2.736 × 10^15 J

oules

8. Answer;

= 2.7 × 10¹⁷ Joules

Solution;

E = mc²; where E is the energy in joules, m is the mass in kg, and c is the speed of light (3.0 10^8 m/s).

Mass = 3 kg

E = 3 kg × (3 × 10⁸ m/s)²

E = 3 kg × 9 × 10¹⁶ m/s²

E = 27 × 10¹⁶ joules

Energy = 2.7 × 10¹⁷ joules

9. Answer;m = 3.3 × 10³ Kg

Solution;E = mc² ; where E is the energy in joules, m is the mass in kg, and c is the speed of light (m/s).

Energy = 3 × 10^20 Joules

Thus; 3 × 10²⁰ = m × (3 * 10^8)²

m = 3 × 10²⁰ / 9 × 10^16

m = 3.3 × 10³Kg

10. Answer;

E = 2.7 × 10⁻¹¹ Joules

Solution;

E = mc²; where E is the energy in joules, m is the mass in kg, and c is the speed of light (m/s).

Mass = 3 × 10^-18 kg

E = (3 × 10⁻²⁸)(3 × 10⁸)²

E = 3 × 10⁻²⁸ × 9 × 10¹⁶

E = 27 × 10⁻¹²

E = 2.7 × 10⁻¹¹ Joules

11. Answer;= 2. 75x 10^-11 Joules

SolutionGiven that; 1 amu= 1.66 x 10-27 kg; 1 J = 1 kg m2/s2)

Mass = 0.184 x 1.66 x10^-27

= 3.054 x 10^-28 kg

E = mc^2

E = 3.054 x 10^-28 kg x (3.0 x10^8 m/s)^2

= 3.054 x 10^-28 kg x 9.0 x 10^16

Energy = 2. 75x 10^-11 Joules

3) the amount of energy released in nuclear reactions is so much larger than the energy released in chemical reactions

4) False

5) True

6) True

7) E = mc²

E = (0.0304)(3*10^8)²

E = 2.736 * 10^15 J

8) E = Mc²

E = 3 kg * (3 * 10⁸ m/s²

E = 3 kg * 9 * 10¹⁶ m/s²

E = 27 * 10¹⁶ kg-m/s²

E = 2.7 * 10¹⁷ kg-m/s²

9) 3 * 10²⁰ = m * 3 * 10⁸

m = 3 * 10²⁰ / 3 * 10⁸

m = 10¹² Kg

10) E = (3 * 10⁻²⁸)(3 * 10⁸)²

E = 3 * 10⁻²⁸ * 9 * 10¹⁶

E = 27 * 10⁻¹²

E = 2.7 * 10⁻¹¹ J

Hope this helps!

A. $192,000

Explanation:

The computation of the labor related overhead cost is shown below:

= (Labor related overhead cost) ÷ (Total direct labor hours) × direct labor hours of X

= ($480,000) ÷ (16,000 hours + 24,000 hours) × 16,000 hours

= $192,000

hence, the correct option is A.