Suppose 64% of a remote mountain village can taste phenylthiocarbamide (ptc) and must, therefore, have at least one copy of the dominant ptc taster allele. if this population conforms to hardy-weinberg equilibrium for this gene, what percentage of the population must be heterozygous for this trait?

The answer is; 48%

This is how to calculate;

Let's assign the dominant allele letter ‘T’ and the recessive letter ‘t’

Using the hardy weignburg equation; p2 + 2pq + q2  = 1

P2 + 2pq = 0.64

q2 = 1 – 0.64 = 0.36

q = 0.6

Remember that; p + q = 1

P = 1 – 0.6 = 0.4

Now to calculate population with herozygour trait = 2pq

2 * 0.4 * 0.6 = 0.48

This means 48% of the population is heterozygous for the trait that enable tasting of phenylthiocarbamide

1)

i))the process of preparing food by green plants in the presence of sunlight is called photosynthesis.

ii) leaf is the site for photosynthesis.

iii) it takes place as,

6h2o+6co2=c6h12o6+602