Using the image below, find the x value for the point that divides the line segment ab into a ratio of 2: 3. a is at negative 4, 6 and b is at 5, 1.
a. −1
b. −0.4
c. 0
d. 0.5

Coordinates of a & b are (-4,6) & (5,1) , respectively.
x1,y1➡-4,6
x2,y2➡5,1
suppose that (x,y) divides ab in ratio 2: 3,then by using section formula for internal division:
x=(m1x2+m2x1)/(m1+m2)
={2×5+3×(-4)}/(2+3)
=(10-12)/5
=-2/5=-0.4↪b