If a man is homozygous dominant for bend fifth finger and a woman is homozygous recessive what’s the probability that the offspring has a fifth bend finger

There is 100 % probability that the child will have bend finger

Explanation:

According to the given information, the father is homozygous dominant (lets assume BB) for bend finger. The bend fifth finger is dominant trait. And the mother is homozygous recessive (bb) for the same trait.

All the gametes of the father would carry "B" allele while the egg cells from given mother would carry "b" allele. Random fertilization of these gametes will give rise to zygote with Bb genotype that will develop into a child with bend finger.

Hence, all of their children will have bend fifth finger.

both male and female gametes are produced by meiosis of the germ cells. therefore, both male and female gametes are haploid. one male and one female gamete unite during the fertilization to form the diploid zygote. in seed bearing plants, pollen grain is the male gametophyte, which produces sperm cells.