To answer this question we need to look at the genetic code to see what amino acid GAC triplet codes.
As is in DNA we need to pass it to RNA
GAC = CUG = Leu
Now we have four possible options, so we need to obtain the RNA triplet and look at the genetic code so we can see what each code.
A.- ATC = UAG = Stop
B.- AAC = UUG = Leu
C.- GAT = CUA = Leu
D.- GAA = CUU = Leu
So options B to D all code for leucine, the same amino acid as the original triplet, meanwhile option A does not code for another triplet but is a Stop codon, meaning that protein production will stop there, so the correct answer is option A as a premature stop definitely will leave the protein unfinished and with no function or defective.
the answer is false?
nucleic acid molecules are incredibly complex, containing the code that guarantees the four different nucleotide units comprise dna, the nucleic acid of interest to the genealogist. and one of four nitrogen-containing molecules called nucleotides