WILL GIVE BRAINLIEST AND 20 POINTS! Barium hydroxide, often used to titrate weak organic acids, is obtained as the octahydrate, Ba(OH)2 * 8 H2O. What mass of Ba(OH)2 * 8 H2O would be required to make 500 mL of a solution that is 0.1500 M hydroxide ions? [hint: calculate the molar mass of barium hydroxide octahydrate].

Barium hydroxide, often used to titrate weak organic acids, is obtained as the octahydrate. Ba(OH)2 • 8H2O. What mass of Ba(OH)2 • 8H2O would be required to make 500.0 mL of a solution that is 0.1500 M in hydroxide ions?

Step-by-Step Solution:

Solution 70P:

Here we have to calculate the mass  of Ba(OH)2 • 8H2O would be required to make 500.0 mL of a solution that is 0.1500 M in hydroxide ions.

Step 1

Given:

Volume of Ba(OH)2 • 8H2O = 500.0 mL or 0.5000 L

Concentration of OH- ion = 0.1500 M

Molecular mass of Ba(OH)2 • 8H2O = 315.4 g

Thus the mass can be calculated as,

0.500L 

= 11.83 g Ba(OH)2.8H2O

Thus the mass of Ba(OH)2 • 8H2O is found to be 11.83 g .

organisms that lack symmetry are called asymmetrical and belong to phylum porifera/sponges.

organisms with specialized stinging cells belong to phylum cnidaria. stinging cells are called cnidoblast cells.

cnidarians show two morphological forms : polyp (sessile) and medusa (mobile)

filter feeding is observed in porifera members.  

alternation of generation is observed in coelenterata or cnidaria. there is alternation of asexual polyp form and sexual medusoid form. it is also referred as metagenesis.