What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four cases? How many phenotypically different kinds of progeny could potentially result from each of the crosses? Aa Bb Cc Dd X aa bb cc dd

Complete question:

What is the probability of producing a child that will phenotypically resemble either one of the two parents in the following four cases? How many phenotypically different kinds of progeny could potentially result from each of the crosses?

a. Aa Bb Cc Dd  × aa bb cc dd

b. aa bb cc dd × AA BB CC DD

c. Aa Bb Cc Dd × Aa Bb Cc Dd

d. aa bb cc dd × aa bb cc dd

a) the probability of producing a child that will phenotypically resemble either one of the two parents is 1/8.

   There will be 16 possible phenotypes among the progeny

b) the probability of producing a child that will phenotypically resemble either one of the two parents is 1.

   There will be one possible phenotype among the progeny

c) the probability of producing a child that will phenotypically resemble either one of the two parents is 81/256 = 0.316.

   There will be 16 possible phenotypes among the progeny

d) the probability of producing a child that will phenotypically resemble either one of the two parents is 1.

   There will be one possible phenotype among the progeny

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

answer; i believe that the correct answer is(d) nondisjunction during meiosis;

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