Please I really need a help here ASAP. It's a physics question. A space ship travels 3.00 ~ 10 km vertically to transport scientists from one particular station to
another. After the transportation, the captain decides to go hizontally 2.00 * 10km to visit an Orie
Calculate its:
a. Distance
b. Displacement​

a).Don't know if you meant to write 3x10^10km and 2x10^10km

I'll solve with this... If they aren't the values... You can then input the real values.

Distance = Total length traveled.

D= 3x10^10 + 2x10^10

D= 5x10^10Km

b) Displacement:

Since it went vertically... Then went horizontally in the second phase... It is forming a right angled Triangle and the Displacement would be the Hypotenuse of this triangle.

Disp.= √ (3x10^10)²+(2x10^10)²

Disp.=3.61x10^10km.

one would be wind another would be water density