Which of the following statements best explains why both prokaryotic and eukaryotic DNA can be moved to become parts of different cells? (1 point) Both prokaryotes and eukaryotes use conjugation, but eukaryotes use conjugation to a greater extent due to a longer mitosis cycles.

Eukaryotes practice conjugation while prokaryotes do not due to shorter chromosome length. Because of this, prokaryotes would suffer more significant deletions.

Prokaryotes can participate in conjugation and transposition. In contrast, eukaryotes cannot move DNA via transposition.

Prokaryotes do this with conjugation, and eukaryotes do this during meiosis.

2.
In a strand of prokaryotic DNA, a segment is excised and placed in another location within the genome. In a strand of eukaryotic DNA, a gene becomes polyploidy.
could account for what is observed for the prokaryotic strand, while could account for what is observed for the eukaryotic strand. (1 point)

Backward slippage on the template strand during replication
Crossing over error
Non-replicative transposition
Replicative transposition

1 or 3; 2 or 4

1 or 4; 1 or 2

3; 1, 2, or 4

4; 1 or 2

3.
A second copy of a gene or chromosome is called (1 point)

antistrophe

polymorphism

polyploidy

syngamy

4.
There are two different strains of bacteria (strain #1 and strain #2). What we know about them is that:
Strain #1 is unable to synthesize methionine and histidine, (met- his-).
Strain #2 is unable to synthesize phenylalanine and tryptophan, (phe- trp-).

When strain #1 and #2 are combined in the same medium, a strain of recombined bacteria that synthesizes all four amino acids (met+ his+ phe+ trp+) results.

Using what we know about these two bacterial strains, a U-tube experiment is performed:
A minimal medium is created within a U-tube (see diagram). Strain #1 is placed in one side of the tube, while strain #2 is placed in the other side of the tube. The bend of the U-tube has a filter that prevents bacterial cells from crossing or coming into contact with one another.

Diagram shows a U-shaped tube filled with yellow liquid. At the bottom of the U, is a circular filter labeled, Medium passes back and forth across filter; cells do not. The yellow liquid on the left side of the filter is labeled, Strain number 1. The yellow liquid on the right side of the filter is labeled, Strain number 2. There is an arrow pointing downward towards a sample dish on both the left and right sides of the tube. Each plate is labeled, Plate on minimal medium and incubate. The sample dish for Strain number 1 is labeled, No growth. The sample dish for Strain number 2 is labeled, Growth of, met+ his+ phe+ trp+, which is the strain of recombined bacteria.

The U-tube experiment result:
The (met+ his+ phe+ trp+) recombination strain appears only on the side of the tube containing Strain 2 (see diagram).

The following intriguing fact is also true:
Fact 1: If Strain 1 is grown in a medium by itself, and that medium is then poured into a plain medium containing Strain 2, NO recombination strain (met+ his+ phe+ trp+) results.

What hypothesis can be reached from learning Fact 1? (1 point)

An information transfer factor that crosses the filter must be produced by Strain 1.

Strain 2 plays a role in causing Strain 1 to produce an information transfer factor that can cross the filter.

Strain 1 cannot be involved in the creation of the new (met+ his+ phe+ trp+) cells.

Strain 1 may have recombinant yeast DNA.

5.
When does the relationship between a virus and a bacterium ultimately result in viral replication and bacterial cell lysis? (1 point)

always

never

some of the time

only with the presence of the F factor